2x^2-10x+16=0

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Solution for 2x^2-10x+16=0 equation: 



2x^2-10x+16=0

a = 2; b = -10; c = +16;
Δ = b2-4ac
Δ = -102-4·2·16
Δ = -28
Delta is less than zero, so there is no solution for the equation

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